1.Find the units digit in $(264)^{102}+(264)^{103}$ A) 0 B) 6 C) 4 D) 2 View Answer Report DiscussAnswer: Option AExplanation:Required units digit=units digit in $(4)^{102}+(4)^{103}$ $4^{2}$ gives unit digit 6 $(4)^{102}$ gives unit digit 6 $(4)^{103}$ gives unit digit of $6\times 4=4$ Unit's digit in (264)^{102} +(264)^{103}=6+4=0
2.Find the total number of prime factors in the expression$4^{11}\times 7^{5}\times 11^{2}$? A) 18 B) 31 C) 29 D) 20 View Answer Report DiscussAnswer: Option CExplanation:$4^{11}\times 7^{5}\times 11^{2}=(2^{2})^{11}\times 7^{5}\times 11^{2}$$=2^{22}\times 7^{5}\times 11^{2}$ Total number of prime factors =22+5+2=29
3.What least value must be assigned to * so that the number 197*5462 is divisible by 9? A) 2 B) 3 C) 1 D) 4 View Answer Report DiscussAnswer: Option AExplanation:Let the missing digit be x Sum of digits =1+9+7+x+5+4+6+2=34+x For 34+x to be divisible by 9, x must be replaced by 2.
4.Which of the following number is not divisible by 4? A) 618703572 B) 67920594 C) 62686440 D) 1765216 View Answer Report DiscussAnswer: Option BExplanation:The number formed by the last 2 digit in the given number 67920594 is not divisible by 4
5.Which digit should come in the place of * and # if the number 62684*# is divisible by both 8 and 5 ? A) 4 and 0 B) 0 and 5 C) 5 and 0 D) 2 and 0 View Answer Report DiscussAnswer: Option AExplanation:Since the given number is divible by 5,So 0 or 5 must come in place of * .But a number ending with 5 is never divisible by 8.Therefore 0 will be in units place The number formed by the last 4 digit is 4 *0which becomes divisible by 8, if * is replaced by 4.
